Answered

Looking for reliable answers? Westonci.ca is the ultimate Q&A platform where experts share their knowledge on various topics. Experience the ease of finding precise answers to your questions from a knowledgeable community of experts. Join our Q&A platform to connect with experts dedicated to providing accurate answers to your questions in various fields.

light strikes a 5.0-cm thick sheet of glass at an angle of incidence in air of 50°. the sheet has parallel faces and the glass has an index of refraction 1.50. a. what is the angle of refraction in the glass? b. after traveling through the glass the light re-emerges into the air. what is the final angle of refraction in air? c. as it leaves the glass, by what distance is the path of the ray is displaced from what it was before entering the glass?

Sagot :

The angle of refraction in the glass is 30°.

Calculation

i= 50°

u= 1.50

u1sini=u2sinr

⇒sinr =[tex]\frac{sin 50}{1.5\\}[/tex]

=0.50=1/2

so angle r = [tex]sin^{-1}[/tex](0.5) =30°

Then we have to calculate r final.

[tex]u_{glass}[/tex]sini= [tex]u_{air}[/tex] sinr

⇒ r = [tex]sin^{-1}[/tex] (1.5 x [tex]\frac{\sqrt{3} }{2}[/tex])

[tex]sin^{-1}[/tex](1.29) = 0.0225

Then the displacement can be calculated as follows:

T= thickness = 5cm

s= t (1- 1/u)

s= 2cm

Thus, all the values have been found out.

To know more about refraction, visit:

https://brainly.com/question/14760207

#SPJ4

We appreciate your time on our site. Don't hesitate to return whenever you have more questions or need further clarification. We hope you found this helpful. Feel free to come back anytime for more accurate answers and updated information. Keep exploring Westonci.ca for more insightful answers to your questions. We're here to help.