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Sagot :
Their final velocity would be 0.118 m/s
Calculation
M1= 168000kg, V1= 0.291 m/s
M2= 117000kg, V2 = 0.128 m/s
According to conservation of momentum,
M1V1 + M2V2 = V(M1+M2)
⇒V = [tex]\frac{168000 * 0.291-117000*0.128}{168000+117000}[/tex]
=[tex]\frac{48888-14976}{285000}[/tex]
=0.118 m/s
Thus, the trains will finally get to the velocity of 0.118 m/s
To know more about velocity, visit:
https://brainly.com/question/18084516
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