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Sagot :
22.23 J/ ∘C g
find heat capacity when 47.0 J of heat is added to 13.0 g of a liquid, its temperature rises by 1.71 ∘C
from the above satement we have got
Q = 47.0 J
MASS = 13.0 g
temperature (T) = 1.71 ∘C
heat capacity ( c ) = ?
NOW, from the formulae , Q = mcΔt
put all the values given in equation
47.0 J = 13.0 g * c * 1.71 ∘C
c = 47.0 ÷ 13.0 * 1.71
c = 47/22
c = 22.23 J/ ∘C g
- heat capacity It is the amount of heat energy required to elevate the temperature of an object by 1 degree celsius.
To know more about heat capacity visit :
https://brainly.com/question/28302909
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