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find heat capacity when 47.0 J of heat is added to 13.0 g of a liquid, its temperature rises by 1.71 ∘C

Sagot :

22.23 J/ ∘C g

find heat capacity when 47.0 J of heat is added to 13.0 g of a liquid, its temperature rises by 1.71 ∘C

from the above satement we have got

Q = 47.0 J

MASS =  13.0 g

temperature (T) = 1.71 ∘C

heat capacity ( c ) = ?

NOW, from the formulae , Q = mcΔt

put all the values given in equation

47.0 J =  13.0 g  * c * 1.71 ∘C

c = 47.0 ÷ 13.0 * 1.71

c = 47/22

c = 22.23 J/ ∘C g

  • heat  capacity   It is the amount of heat energy required to elevate the temperature of an object by 1 degree celsius.

To know more about heat  capacity visit :

https://brainly.com/question/28302909

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