Answered

Welcome to Westonci.ca, your go-to destination for finding answers to all your questions. Join our expert community today! Get accurate and detailed answers to your questions from a dedicated community of experts on our Q&A platform. Explore comprehensive solutions to your questions from knowledgeable professionals across various fields on our platform.

A large balloon is initially filled to a volume of 11.2 L at 325 K and a pressure of 3450 mm Hg. What volume of gas will the balloon contain at 1.4 atm and 325 K?

Sagot :

CrystalQueen

Answer:

36 L

Explanation:

Since the temperature remains constant, you can use Boyle's Law to find the final volume:

P₁V₁ = P₂V₂

In this formula, "P₁" and "V₁" represent the initial pressure and volume. "P₂" and "V₂" represent the final pressure and volume. Before, you can plug the given values into the equation and solve for "V₂", you need to convert mmHg to atm to maintain consistent units.

760 mmHg = 1 atm

P₁ = 3,450 mmHg / 760 mmHg = 4.54 atm      P₂ = 1.4 atm

V₁ = 11.2 L                                                            V₂ = ? L

P₁V₁ = P₂V₂                                                  <----- Boyle's Law

(4.54 atm)(11.2 L) = (1.4 atm)V₂                    <----- Insert values

50.848 = (1.4 atm)V₂                                   <----- Multiply 4.54 and 11.2

36 = V₂                                                        <----- Divide both sides by 1.4

We appreciate your time. Please come back anytime for the latest information and answers to your questions. We appreciate your visit. Our platform is always here to offer accurate and reliable answers. Return anytime. Your questions are important to us at Westonci.ca. Visit again for expert answers and reliable information.