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Divide 102 dollars among 3 boys. A,B, and C, so that A gets twice as much as B and C gets 1 1/2 times as much as A. How much does each boy get?

Sagot :

B=x
A=2x
C=2x*1.5=3x

6x=102
x=17

A=34
B=17
C=51

Boy A gets $34, boy B gets $17 and boy C gets $51 and this can be determined by forming the linear equation and by using the arithmetic operations.

Given :

  • Total Amount = $102
  • Total number of boys = 3
  • A gets twice as much as B and C gets 1.5 times as much as A.

It is given that A gets twice as much as B, that is:

A = 2B

[tex]\rm 0.5 A = B[/tex]  ----- (1)

It is also given that C gets 1.5 times as much as A, that is:

[tex]\rm C = 1.5 A[/tex]  ------ (2)

Given that the total amount is $102, that is:

A + B + C = 102 --- (3)

Now, put the value of B and C in equation (3).

[tex]\rm A+0.5A+1.5A = 102[/tex]

3A = 102

A = $34

Now, put the value of A in equations (1) and (2).

[tex]\rm B = 0.5\times 34[/tex]

B = $17

[tex]\rm C = 1.5\times 34[/tex]

C = $51

Boy A gets $34, boy B gets $17 and boy C gets $51.

For more information, refer to the link given below:

https://brainly.com/question/17921485