Answered

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Find three consecutive integers such that the sum of twice the smallest and 3 times the largest is 126.

Sagot :

x-smallest
y middle
z largest


x+1=y
y+1=z
2x+3z=126

2x+ 3(y+1)=126
2x+3y+3=126
2x+3(x+1)=123
5x=120
x=24

y=25

z=26



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