At Westonci.ca, we connect you with experts who provide detailed answers to your most pressing questions. Start exploring now! Get immediate and reliable answers to your questions from a community of experienced experts on our platform. Join our Q&A platform to connect with experts dedicated to providing accurate answers to your questions in various fields.
Sagot :
[tex]4x^2-28x+49=5 \\ \\4x^2-28x+49-5=0\\ \\4x^2-28x+44=0\\ \\ \Delta = b^{2}-4ac =(-28)^{2}-4*4*44=784 - 704 = 80 \\ \\x_{1}=\frac{-b-\sqrt{\Delta }}{2a} =\frac{28- \sqrt{80}}{2*4}=\frac{-28-\sqrt{16*5}}{8}= \frac{-28-4\sqrt{ 5}}{8}=\\ \\=\frac{\not4^1(-7- \sqrt{ 5})}{\not8^2}=\frac{ -7- \sqrt{ 5} }{2}=[/tex]
[tex]x_{2}=\frac{-b+\sqrt{\Delta }}{2a} =\frac{28+\sqrt{80}}{2*4}=\frac{-28+\sqrt{16*5}}{8}= \frac{-28+4\sqrt{ 5}}{8}=\\ \\=\frac{\not4^1(-7+ \sqrt{ 5})}{\not8^2}=\frac{ -7+ \sqrt{ 5} }{2} \\ \\Answer : x=\frac{ -7- \sqrt{ 5} }{2} \ \ or \ \ x =\frac{ -7+ \sqrt{ 5} }{2}[/tex]
[tex]x_{2}=\frac{-b+\sqrt{\Delta }}{2a} =\frac{28+\sqrt{80}}{2*4}=\frac{-28+\sqrt{16*5}}{8}= \frac{-28+4\sqrt{ 5}}{8}=\\ \\=\frac{\not4^1(-7+ \sqrt{ 5})}{\not8^2}=\frac{ -7+ \sqrt{ 5} }{2} \\ \\Answer : x=\frac{ -7- \sqrt{ 5} }{2} \ \ or \ \ x =\frac{ -7+ \sqrt{ 5} }{2}[/tex]
We hope this was helpful. Please come back whenever you need more information or answers to your queries. We hope this was helpful. Please come back whenever you need more information or answers to your queries. Thank you for trusting Westonci.ca. Don't forget to revisit us for more accurate and insightful answers.