monkyman3
Answered

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Determine the quantity of work done when a crane lifts a 100-N block from 2 m above the ground to 6 m above the ground.

A.
100 J

B.
200 J

C.
400 J

D.
600 J

Sagot :

Answer:

C.  400 J

Explanation:

In physics, work is defined as

[tex]W=F \times \Delta d[/tex]

Where [tex]W[/tex] is the word done, [tex]F[/tex] is the force that move the object and [tex]\Delta d[/tex] is the change of the position of the object.

In this case, we have

[tex]F= 100 \ N[/tex]

[tex]\Delta d= 6m - 2m = 4m[/tex], remember that the difference refers to the actual subtraction between the final point and the initial point of the object.

Replacing these values, we have

[tex]W= 100 \ N \times 4m\\W=400 \ Joules[/tex]

Therefore, the right answer is C. The work done is 400 Joules

haydenprossi

Answer:

400 J

Explanation:

I just took the test and can confirm this.

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