hfelltennis
Answered

Welcome to Westonci.ca, the place where your questions find answers from a community of knowledgeable experts. Discover a wealth of knowledge from experts across different disciplines on our comprehensive Q&A platform. Our platform provides a seamless experience for finding reliable answers from a network of experienced professionals.

Look Down Below For question:

Look Down Below For Question class=

Sagot :

naǫ
the cattle train
speed - 36.5 km/h
time - x h

the passenger train
speed - 29.2 km/h
time - (2.4+x) h

The cattle train caught up to the passenger train so the distance they travelled is the same.
Distance is speed times time.

[tex]36.5 \times x=29.2 \times (2.4+x) \\ 36.5x=70.08+29.2x \\ 36.5x-29.2x=70.08 \\ 7.3x=70.08 \\ x=\frac{70.08}{7.3} \\ x=9.6 \\ \\ 2.4+x=2.4+9.6=12[/tex]

The passenger train travelled for 12 hours before the cattle train caught up.
Used brute force to figure this one out and got lucky at t=12.

What you need to know:

[tex]d=\left| x-y \right| [/tex]

t = time travelled (in hours)

x = distance passenger train has travelled

y = distance cattle train has travelled

d = distance between both trains in km

------------------------------------

RESULTS AND TIME SNAPSHOTS:

When:

t=0, x=0, y=0, d=0

t=2.4, x=70.08, y=0, d=70.08

t=4.8, x=140.16, y=87.6, d=52.56

t=7.2, x=210.24, y=175.2, d=35.04

t=9.6, x=280.32, y=262.8, d=17.52

t=12, x=350.4, y=350.4, d=0 <-------

So your answer is 12 hours.
Thank you for your visit. We're dedicated to helping you find the information you need, whenever you need it. We hope this was helpful. Please come back whenever you need more information or answers to your queries. Westonci.ca is here to provide the answers you seek. Return often for more expert solutions.