hfelltennis
Answered

Welcome to Westonci.ca, where you can find answers to all your questions from a community of experienced professionals. Get quick and reliable solutions to your questions from a community of experienced experts on our platform. Experience the convenience of finding accurate answers to your questions from knowledgeable experts on our platform.

Look Down Below For question:

Look Down Below For Question class=

Sagot :

naǫ
the cattle train
speed - 36.5 km/h
time - x h

the passenger train
speed - 29.2 km/h
time - (2.4+x) h

The cattle train caught up to the passenger train so the distance they travelled is the same.
Distance is speed times time.

[tex]36.5 \times x=29.2 \times (2.4+x) \\ 36.5x=70.08+29.2x \\ 36.5x-29.2x=70.08 \\ 7.3x=70.08 \\ x=\frac{70.08}{7.3} \\ x=9.6 \\ \\ 2.4+x=2.4+9.6=12[/tex]

The passenger train travelled for 12 hours before the cattle train caught up.
Used brute force to figure this one out and got lucky at t=12.

What you need to know:

[tex]d=\left| x-y \right| [/tex]

t = time travelled (in hours)

x = distance passenger train has travelled

y = distance cattle train has travelled

d = distance between both trains in km

------------------------------------

RESULTS AND TIME SNAPSHOTS:

When:

t=0, x=0, y=0, d=0

t=2.4, x=70.08, y=0, d=70.08

t=4.8, x=140.16, y=87.6, d=52.56

t=7.2, x=210.24, y=175.2, d=35.04

t=9.6, x=280.32, y=262.8, d=17.52

t=12, x=350.4, y=350.4, d=0 <-------

So your answer is 12 hours.
Thank you for choosing our platform. We're dedicated to providing the best answers for all your questions. Visit us again. We appreciate your time. Please come back anytime for the latest information and answers to your questions. Find reliable answers at Westonci.ca. Visit us again for the latest updates and expert advice.