[tex]\rm\sum_{k = 1}^ \infty \frac{1}{k(k + n)} = \frac{H_n}{n} \\ [/tex]

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30-09-2022
Mathematics

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[tex]\rm\sum_{k = 1}^ \infty \frac{1}{k(k + n)} = \frac{H_n}{n} \\ [/tex]

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