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Sagot :
Answer:
Anthony is 16, Chase is 11, Trinity is 32
Step-by-step explanation:
This is going to be very lengthy!
[tex]x= Anthony, y= Chase, z= Trinity[/tex]
---
1. [tex]x=y+5[/tex]
2. [tex]z=2x[/tex]
3. [tex]x+y+z=59[/tex]
Anthony is 5 years older than Chase, so Chase's Age + 5 is equal to Anthony's age
Trinity is twice as old as Anthony, so Trinity is 2*Anthony's age
Their sum is 59, so all of their ages added together should equal 59
Since this is a system of three equations, you have to shrink it down to 2 equations with only 2 variables. To do that, I'll be using elimination between 2 equations 1 at a time. Matrices would be faster and cleaner, but I'll do it algebraically!
1 & 2:
[tex]x-y=5\\-2x+z=0\\---\\2x-2y=10\\-2x+z=0\\---\\-2y+z=10[/tex]
This is going to be one of my new equations since it now only has 2 variables, which we want! NOTE: Whicever variable you eliminate from the first equation, you HAVE TO eliminate that some one from the reminaing two equations.
2 & 3:
[tex]-2x+z=0\\x+y+z=59\\---\\-2x+z=0\\2x+2y+2z=118\\---\\2y+3z=118[/tex]
Notice how I have 2 equations, both with the same variables (y & z). I can use those two now to create a system of 2 equations!
[tex]-2y+z=10\\2y+3z=118\\---\\4z=128\\z=32\\---\\-2y+32=10\\-2y=-22\\y=11\\---\\32=2x\\x=16[/tex]
Anthony is 5 years older than Chase: [tex]11+5=16[/tex] is true
Trinity is twice as old as Anthony: [tex]16*2=32[/tex] is true
Their sum is 59: [tex]16+11+32=59[/tex] is true
Hope that helps!
Answer:
Anthony is 16 years old.
Chase is 11 years old
Trinity is 32 years old.
Step-by-step explanation:
Define the variables:
- Let a = Anthony's age
- Let c = Chase's age
- Let t = Trinity's age
Given information:
- Anthony is five years older than Chase.
- Trinity is twice as old as Anthony.
- The sum of their ages is 59.
Create 3 equations from the given information and defined variables:
[tex]\textsf{Equation 1}: \quad a = c + 5[/tex]
[tex]\textsf{Equation 2}: \quad t = 2a[/tex]
[tex]\textsf{Equation 3}: \quad a + c + t = 59[/tex]
Rearrange Equation 1 to isolate c:
[tex]\implies c=a-5[/tex]
Substitute this and Equation 2 into Equation 3 and solve for a:
[tex]\implies a+c+t=59[/tex]
[tex]\implies a+a-5+2a=59[/tex]
[tex]\implies 4a-5=59[/tex]
[tex]\implies 4a-5+5=59+5[/tex]
[tex]\implies 4a=64[/tex]
[tex]\implies \dfrac{4a}{4}=\dfrac{64}{4}[/tex]
[tex]\implies a=16[/tex]
Substitute the found value of a into Equation 1 and solve for c:
[tex]\implies a=c+5[/tex]
[tex]\implies 16=c+5[/tex]
[tex]\implies 16-5=c+5-5[/tex]
[tex]\implies c=11[/tex]
Substitute the found value of a into Equation 2 and solve for t:
[tex]\implies t=2a[/tex]
[tex]\implies t=2(16)[/tex]
[tex]\implies t=32[/tex]
Therefore:
- Anthony is 16 years old.
- Chase is 11 years old
- Trinity is 32 years old.
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