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A 15% solution of KOH (Mr = 56.11 , d=1.137 g dm^-3) reacted with 200 mL of 20% solution of H2SO4; (Mr =98.08; d=1.139 g dm^-3). What volume of 15% KOH solution was needed and how many grams of K2SO4; (Mr = 174.26) were prepared?

KOH + H2SO4 = K2SO4 + H2O

Sagot :

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