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Question 6 of 10
Solve the equation x= π³ for r.
X=
OA. r= √3x (2π)
OB. T = √ 2T
C. r = √3x - 2π
= √²/
3x
OD. r=₁
A

Question 6 Of 10 Solve The Equation X Π For R X OA R 3x 2π OB T 2T C R 3x 2π 3x OD R A class=

Sagot :

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