m/SQR = (2x+6)° and m/PQR = (10x - 5)° and
m/SQP = 61°.
Find m/SQR and m/PQR.

Question

03-10-2022
Mathematics

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m/SQR = (2x+6)° and m/PQR = (10x - 5)° and
m/SQP = 61°.
Find m/SQR and m/PQR.

Sagot :

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