Answered

Looking for trustworthy answers? Westonci.ca is the ultimate Q&A platform where experts share their knowledge on various topics. Connect with a community of professionals ready to provide precise solutions to your questions quickly and accurately. Get precise and detailed answers to your questions from a knowledgeable community of experts on our Q&A platform.

Drag the tiles to the correct boxes to complete the pairs.
Match the pairs of equivalent expression

Drag The Tiles To The Correct Boxes To Complete The Pairs Match The Pairs Of Equivalent Expression class=

Sagot :

semsee45

Answer:

[tex]\boxed{\frac{7}{5}y} \longrightarrow \boxed{y+\frac{2}{5}y}[/tex]

[tex]\boxed{0.68y} \longrightarrow \boxed{y-0.32y}[/tex]

[tex]\boxed{\frac{3}{5}y} \longrightarrow \boxed{y-\frac{2}{5}y}[/tex]

[tex]\boxed{1.32y} \longrightarrow \boxed{y+0.32y}[/tex]

Step-by-step explanation:

[tex]\begin{aligned}\implies y-0.32y & = 1y-0.32y\\& = (1-0.32)y\\& = 0.68y\end{aligned}[/tex]

[tex]\begin{aligned}\implies y+0.32y & = 1y+0.32y\\& = (1+0.32)y\\& = 1.32y\end{aligned}[/tex]

[tex]\begin{aligned}\implies y+\dfrac{2}{5}y & = 1y+\dfrac{2}{5}y\\& = \dfrac{5}{5}y+\dfrac{2}{5}y\\& = \left(\dfrac{5}{5}+\dfrac{2}{5}\right)y\\& = \left(\dfrac{5+2}{5}\right)y\\& = \dfrac{7}{5}y\\\end{aligned}[/tex]

[tex]\begin{aligned}\implies y-\dfrac{2}{5}y & = 1y-\dfrac{2}{5}y\\& = \dfrac{5}{5}y-\dfrac{2}{5}y\\& = \left(\dfrac{5}{5}-\dfrac{2}{5}\right)y\\& = \left(\dfrac{5-2}{5}\right)y\\& = \dfrac{3}{5}y\\\end{aligned}[/tex]

Thank you for visiting. Our goal is to provide the most accurate answers for all your informational needs. Come back soon. Your visit means a lot to us. Don't hesitate to return for more reliable answers to any questions you may have. We're glad you visited Westonci.ca. Return anytime for updated answers from our knowledgeable team.