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Sagot :
Answer:
see explanation
Step-by-step explanation:
consider the perfect squares on either side of 99 , that is
81 < 99 < 100 , then
[tex]\sqrt{81}[/tex] < [tex]\sqrt{99}[/tex] < [tex]\sqrt{100}[/tex] , that is
9 < [tex]\sqrt{99}[/tex] < 10
now 99 is closer to 100 than it is to 81
then [tex]\sqrt{99}[/tex] is almost 10
Answer:
Step-by-step explanation:
Smaller perfect squares near 99 is 81
Larger perfect square near 99 is 100
First step would be to find the two perfect squares that lies between on the number line. I could then think about the number 99 and how close it is to the smaller perfect square and the larger perfect square. That could tell me how far above or below the of the two perfect squares 99 lies on the number line. I could then take the square root of the perfect squares to see how I would estimate the square root of 99. The √99 is almost 10.
81 < 99 < 100
√81 < √99 < √100
8 < √99 < 10
So, √99 is almost 10.
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