What happens to the function ƒ(x) = (x − 1)² + 1 when it becomes f'(x) = (1/3 x − 1)² + 1?
It is stretched away from the y-axis.
It is stretched away from the x-axis.
It is compressed toward the x-axis.
O It is compressed toward the y-axis.

Question

04-10-2022
Mathematics

Answered

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What happens to the function ƒ(x) = (x − 1)² + 1 when it becomes f'(x) = (1/3 x − 1)² + 1?
It is stretched away from the y-axis.
It is stretched away from the x-axis.
It is compressed toward the x-axis.
O It is compressed toward the y-axis.

Sagot :

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What happens to the function ƒ(x) = (x − 1)² + 1 when it becomes f'(x) = (1/3 x − 1)² + 1? It is stretched away from the y-axis. It is stretched away from the x-axis. It is compressed toward the x-axis. O It is compressed toward the y-axis.

Sagot :

Other Questions

What happens to the function ƒ(x) = (x − 1)² + 1 when it becomes f'(x) = (1/3 x − 1)² + 1?
It is stretched away from the y-axis.
It is stretched away from the x-axis.
It is compressed toward the x-axis.
O It is compressed toward the y-axis.