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What is the inverse of f (x) = (2x + 1)² for x ≥-1/?
○ ƒ−¹(x) = ½⁄3 (√x – 1) for x ≥ 1/1/
O ƒ−¹(x) = − ¼½ (√x + 1) for x ≥ 1/1/
ƒ-¹(x) = −(√x+1) for x ≥ 0
O f-¹(x)=(√x - 1) for x ≥ 0

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