Answered

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(PLEASE HURRY
(CH4).
Methane
to this equation:
ammonia
48 g
(NH3). and oxygen can react to form hydrogen cyanide (HCN)
2 CH4 + 2 NH3 + 3O2 → 2HCN + 6H₂O
About how many grams of methane are required to produce 1 mole of HCN?
16 g
O 24 g
O 34 g
and water according

PLEASE HURRY CH4 Methane To This Equation Ammonia 48 G NH3 And Oxygen Can React To Form Hydrogen Cyanide HCN 2 CH4 2 NH3 3O2 2HCN 6HO About How Many Grams Of Me class=

Sagot :

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