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The measures of the angles of a triangle are shown in the figure below. Solve for x.
(4x-5)°
(3x-3)


The Measures Of The Angles Of A Triangle Are Shown In The Figure Below Solve For X 4x5 3x3 class=

Sagot :

Answer: x = 88/7 or 12.5714285714

Step-by-step explanation:

All sides of a triangle add up to 180.

Therefore...

90 + (4x + 5) + (3x - 3) = 180

(4x + 5) + (3x - 3) = 90

4x + 5 + 3x - 3 = 90

7x + 2 = 90

7x = 88

x = 88/7 or 12.5714285714

Answer:

x = 14

Step-by-step explanation:

Interior angles of a triangle sum to 180°.

Therefore, the find the value of x, sum the given angles, equal them to 180 and solve for x:

[tex]\begin{aligned}\implies (4x-5)+(3x-3)+90&=180\\ 4x-5+3x-3+90&=180\\ 4x+3x-5-3+90&=180\\ 7x+82&=180\\ 7x+82-82&=180-82\\ 7x&=98\\\dfrac{ 7x}{7}&=\dfrac{98}{7}\\x&=14\end{aligned}[/tex]

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