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Convert the volume of calcium chloride solution required from liters to
Na₂CO3(aq) +CaCl₂(aq) → 2 NaCl(aq) + CaCO3(s)
Calculate the volume (in mL) of 0.100 M CaCl₂ needed to produce 1.00 g of
.There is an excess of Na₂CO3.
Molar mass of calcium carbonate = 100.09 g/mol
Volume of calcium chloride =
dmL
CaCO3(s)
