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A different mass of sodium hydroxide was used to make another 25.0 cm' solution.
35.0 cm' of 0.250 mol/dm' hydrochloric acid was required to neutralise this solution.
Calculate the mass of sodium hydroxide in the 25.0 cm' solution that was used in the titration.
Relative formula mass (M) of NaOH = 40
Mass=..
[4]

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