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particle 1 carrying -4.0 μc of charge is fixed at the origin of an xy coordinate system, particle 2 carrying 8.0 μc of charge is located on the x axis at x

Sagot :

The phenomenona of vectors proved.

What is vector?

vector is a quantity that has two independent properties magnitude and direction.

The electric force is given by coulumb's law

          F = k q₁q₂ / r²

Let's apply newtons second law in particle 3

         F = F₃₁ - F₃₂

        F₃₁ = k q₃q₁ / r₃₁²

         F₃₂ = k q₃q₂ / r₃₂²

Let's write the values ​​they give us

         q₁ = -4.0 10⁻⁶ C

         x₁ = 0

         q₂ = q₃ = + 8.0 10⁻⁶ C

         x₂ = 4.0 m

         x₃ = -4.0 m

We look for the distances

        r₃₁ = x₃ -x₁

         r₃₁ = -4.0  - 0 = -4.0 m

         r₃₂ = -4.0 - 4.0 = -8.0 m

Let's write the force equation

         F = k q₃ (q₁ / r₃₁² + q₂ / r₃₂²)

so let's  calculate

          F =  8.99 10⁹ 8 10⁻⁶  (4 10-6/4 2 - 8 10-6 / 8 2)

          F =  71.92 10³ (1/2 - 1/8  )10⁻⁶

         F =   26.97 10-3 N

None of the charge are on the axis and therefore there are no forces on this axis.

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