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Sagot :
Paper: 3/ 3/ 3/ 3
Ribbon: 4/ 5/ 6/ leftover 3
Kites: 3/ 3/ 3/ 3
Leftover: 1/ 2/ 3/ 0
Make a graph like that that solves the problem.
Ribbon: 4/ 5/ 6/ leftover 3
Kites: 3/ 3/ 3/ 3
Leftover: 1/ 2/ 3/ 0
Make a graph like that that solves the problem.
Answer:
12 kites because 12 is the least common multiple of 3 and 4
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