Welcome to Westonci.ca, where you can find answers to all your questions from a community of experienced professionals. Our platform connects you with professionals ready to provide precise answers to all your questions in various areas of expertise. Our platform provides a seamless experience for finding reliable answers from a network of experienced professionals.
Sagot :
So you don't know the value of x, y, or z; all you're told is to solve for x. This is not impossible (even though it may seem like it). Your answer will have several variables in it, but in algebra you won't always have the complete answer.
Start with the equation: 4x - 5 / y = 2z
The first thing you'll want to do to it is try to get x alone on one side.
4x - 5 / y = 2z
+5 +5 --> 4x / y = 2z +5
*y *y --> 4x = y (2z + 5)
/4 /4 --> x = (y (2z + 5)) / 4
Your final answer will be: x = (y (2z +5)) / 4
Hope it makes sense to you!!
Start with the equation: 4x - 5 / y = 2z
The first thing you'll want to do to it is try to get x alone on one side.
4x - 5 / y = 2z
+5 +5 --> 4x / y = 2z +5
*y *y --> 4x = y (2z + 5)
/4 /4 --> x = (y (2z + 5)) / 4
Your final answer will be: x = (y (2z +5)) / 4
Hope it makes sense to you!!
[tex]4x- \frac{5}{y}=2z \\ + \frac{5}{y}\ \ \ \ \ \ +\frac{5}{y} \\ 4x=2z+ \frac{5}{y} \\ /4\ \ \ \ \ /4 \\ \boxed{x= \frac{2}{4}z+ \frac{20}{y}} [/tex]
Thanks for stopping by. We are committed to providing the best answers for all your questions. See you again soon. We hope our answers were useful. Return anytime for more information and answers to any other questions you have. Get the answers you need at Westonci.ca. Stay informed with our latest expert advice.