Welcome to Westonci.ca, your one-stop destination for finding answers to all your questions. Join our expert community now! Get immediate answers to your questions from a wide network of experienced professionals on our Q&A platform. Experience the ease of finding precise answers to your questions from a knowledgeable community of experts.
Sagot :
So you don't know the value of x, y, or z; all you're told is to solve for x. This is not impossible (even though it may seem like it). Your answer will have several variables in it, but in algebra you won't always have the complete answer.
Start with the equation: 4x - 5 / y = 2z
The first thing you'll want to do to it is try to get x alone on one side.
4x - 5 / y = 2z
+5 +5 --> 4x / y = 2z +5
*y *y --> 4x = y (2z + 5)
/4 /4 --> x = (y (2z + 5)) / 4
Your final answer will be: x = (y (2z +5)) / 4
Hope it makes sense to you!!
Start with the equation: 4x - 5 / y = 2z
The first thing you'll want to do to it is try to get x alone on one side.
4x - 5 / y = 2z
+5 +5 --> 4x / y = 2z +5
*y *y --> 4x = y (2z + 5)
/4 /4 --> x = (y (2z + 5)) / 4
Your final answer will be: x = (y (2z +5)) / 4
Hope it makes sense to you!!
[tex]4x- \frac{5}{y}=2z \\ + \frac{5}{y}\ \ \ \ \ \ +\frac{5}{y} \\ 4x=2z+ \frac{5}{y} \\ /4\ \ \ \ \ /4 \\ \boxed{x= \frac{2}{4}z+ \frac{20}{y}} [/tex]
Visit us again for up-to-date and reliable answers. We're always ready to assist you with your informational needs. We appreciate your visit. Our platform is always here to offer accurate and reliable answers. Return anytime. Thank you for choosing Westonci.ca as your information source. We look forward to your next visit.