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Chile rode her bicycle from her house directly to the library in 4 minutes. The library is 1 mile from her house.

Part A: What is Chloe's speed in miles per hour? Show your work and explain you reasoning.


Part B: Chloe's trip back to her house took twice as long as her trip to the library. What was Chloe's average speed for the entire trip (from her house to the library and back to her house)? Show your work and explain your reasoning.
A.K.A : I need this now!!!!!

Sagot :

ranya14591
Chile's speed is 60/4 * 1 = 15 mph
Chile's speed on her way back = 15/2 = 7.5 mph
Chile's average speed = (15+7.5) / 2 = 11.25 mph
isyllus

Answer:

Part A) Speed of Chloe's bicycle from her house to the library = 15 mph

part B) Average speed  = 10 mph

Step-by-step explanation:

Chile rode her bicycle from her house directly to the library in 4 minutes. The library is 1 mile from her house.

Distance between house and library = 1 mile

Time taken from house to library = 4 minutes

As we know, 60 minutes =  1 hour

So, 4 minutes [tex]=\dfrac{1}{15}\ h[/tex]

[tex]\text{Speed} = \dfrac{\text{distance}}{\text{time}}[/tex]

[tex]\text{Speed}=\dfrac{1}{1/15}=15\text{ mph}[/tex]

Part A:

Speed of Chloe's bicycle from her house to the library = 15 mph

Part B: Chloe's trip back to her house took twice as long as her trip to the library.

  • From house to library:-

Distance =  1 mile

Time [tex]=\dfrac{1}{15}\ h[/tex]

  • From library to house

Distance =  1 mile

Time [tex]=\dfrac{2}{15}\ h[/tex]

[tex]\text{Average speed}=\dfrac{\text{Total distance}}{\text{Total time}}[/tex]

[tex]\text{Average speed}=\dfrac{1+1}{\frac{1}{15}+\frac{2}{15}}[/tex]

[tex]\text{Average speed}=\dfrac{2}{\frac{3}{15}}[/tex]

Average speed  = 10 mph

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