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what is the solution to 12x+4y=6 and 3x+y=-6

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konrad509
[tex]12x+4y=6|\div 2 \\ 3x+y=-6|\cdot(-2)\\\\ 6x+2y=3\\ \underline{-6x-2y=12}\\ 0=15\\\\ x,y\in\emptyset [/tex]
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