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PLEASE HELP. How would you solve -2<=(3/5)z+(4/5)<6 for Z.

Sagot :

konrad509
[tex]-2\leq\dfrac{3}{5}z+\dfrac{4}{5}<6 \\ -10\leq3z+4<30\\ -14\leq3z<26\\ -\dfrac{14}{3}\leq z<\dfrac{26}{3}\\ z\in\left[-\dfrac{14}{3},\dfrac{26}{3}\right)[/tex]
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