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Estimate the sum or difference 1/8+1/4

Sagot :

W0lf93
to estimate the sum of difference of 1/8 +1/4, the method is as follows: Rule1 a/b +c/d = (axd) + (bxc) /bxd and Rule2: a/b - c/d = (axd) - (bxc) /bxd. let A=1/8 +1/4=(1x4) +(8x1) / /8x4=4+8 /32=12/32=3/8, and then A=1/8-1/4=4-8/32= -6/32= -3/16. So A=1/8 +1/4=3/8 and A=1/8 -1/4=-3/16Hope this helps. Let me know if you need additional help!
carlosego

For this case we have the following expression:

[tex] \frac{1}{8} + \frac{1}{4} [/tex]

To make the addition more easily, we can rewrite the expression so that we have the same denominator in both terms.

We have then:

[tex] \frac{1}{8} + \frac{1}{4} =\frac{1}{8} + \frac{1}{4}.\frac{2}{2} [/tex]

[tex] \frac{1}{8} + \frac{1}{4} =\frac{1}{8} + \frac{2}{8} [/tex]

Since we have the same denominator, we can add the numerators and place the same denominator.

We have then:

[tex] \frac{1}{8} + \frac{1}{4} = \frac{1+2}{8} [/tex]

[tex] \frac{1}{8} + \frac{1}{4} = \frac{3}{8} [/tex]

Answer:

The total sum is given by:

[tex] \frac{1}{8} + \frac{1}{4} = \frac{3}{8} [/tex]

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