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Sagot :
Primero que todo es necesario escribir una equacion que describa el total de plata que hay en el cerdito. para eso vamos a llamar y al total de los ahorros, X1 a las monedas de 25 centavos, X2 a las monedas de diez centavos y X3 a las monedas de 5 centavos, entonces la equacion general sera:
[tex]y=0.25x_1+0.10x_2+0.05x_3[/tex]ahora podemos remplazar los valores de y, X1 y X2 con los datos que nos dan en el problema:
[tex]7.650=(0.25)\cdot15+(0.10)\cdot19+0.05x_3[/tex]Y resolvemos la equacion para X3
[tex]\begin{gathered} 7.65=3.75+1.9+0.05x_3 \\ 7.65-3.75-1.9=0.05x_3 \\ \frac{2}{0.05}=x_3 \\ 40=x_3 \end{gathered}[/tex]Lo que significa que ella tiene 40 monedas de 5 centavos
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