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could someone help me with this please?
Objective: Determine the thickness of Aluminum foil in both cm and atom units.

Given Information:

Density of Aluminum = 2.70 g/cm3

Diameter of Aluminum Atom = .0000000286 cm

Volume of Sample = Mass of Sample / Density of Sample

Volume of Sample = L x W x H*

(*H = thickness of sample)

Data and Results

Include any data collected, calculations, and results below.
(Pictures of your work are fine.)

Conclusion

Aluminum foil is _________ cm thick.

Aluminum foil is _________ atoms thick.

Sagot :

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