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Sagot :
GIVEN:
We are told that a customer borrowed $2000 and then $1000 both at the rate of 10% for 1 year.
Required;
To determine how much he would have saved if he had taken a loan of $3000 at the rate of 8% for 1 year instead.
Step-by-step solution;
We will calculate the interest charged on the loans of $2000 and $1000 as follows;
[tex]\begin{gathered} Int_{2k}=P\times R\times T \\ \\ Where\text{ }you\text{ }have: \\ P=principal(2000),R=rate(10\%),T=time(1\text{ }year) \\ \\ Int_{2k}=2000\times0.10\times1 \\ \\ Int_{2k}=200 \end{gathered}[/tex]Also, we have;
[tex]\begin{gathered} Int_{1k}=P\times R\times T \\ \\ Int_{1k}=1000\times0.10\times1 \\ \\ Int_{1k}=100 \end{gathered}[/tex]This means the interest payable on both loans will be $300 (200 + 100).
To determine the amount of interest payable on the loan of $3000;
[tex]\begin{gathered} Int_{3k}=P\times R\times T \\ \\ Int_{3k}=3000\times0.08\times1 \\ \\ Int_{3k}=240 \end{gathered}[/tex]Observe that the customer would be paying less if he had taken one sum of $3000 at the rate of 8%, and therefore the amount he would have saved is;
[tex]\begin{gathered} Int\text{ }saved=300-240 \\ \\ Int\text{ }saved=60 \end{gathered}[/tex]ANSWER:
Option A is the correct answer. The customer would have saved $60
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