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write an equation in slope-intercept form for the line that is parallel to y= -4x -3 and that passes through the point (-2,4)

Write An Equation In Slopeintercept Form For The Line That Is Parallel To Y 4x 3 And That Passes Through The Point 24 class=

Sagot :

The equation of the line given is,

[tex]y=-4x-3[/tex]

We were told that a line is parallel to the equation.

Therefore, from the equation above, the slope of the line is

[tex]m_1=-4[/tex]

Rule for paralel line

[tex]m_1=m_2[/tex]

Hence, the slope (m2) is

[tex]-4[/tex]

Also, the line passes through the point (-2,4).

The formula to calculate the equation in sope-intercept dform is,

[tex]y-y_1=m(x-x_1)[/tex]

where,

[tex](x_1,y_1)=(-2,4)[/tex]

Therefore,

[tex]y-4=-4(x-(-2))[/tex]

Simplify

[tex]\begin{gathered} y-4=-4(x+2) \\ y-4=-4x-8 \\ y=-4x-8+4 \\ y=-4x-4 \end{gathered}[/tex]

Hence, the equation of theline is

[tex]y=-4x-4\text{ \lparen Option 3\rparen}[/tex]

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