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Sagot :
a) The efficiency of this carnot engine = 0.672 = 67.2%
Carnot heat engine converts 67.2% of the heat it receives to work.
b) The amount of heat rejected to the sink per cycle = 164 kJ
[tex]Q_{H}[/tex] = 500 kJ
Efficiency of this carnot engine =?
Amount of heat rejected to the sink per cycle =?
a) Carnot heat engine is a reversible heat engine; its efficiency can be calculated from:
[tex]n_{th,rev} = 1 - \frac{T_{L} }{T_{H} }[/tex]
[tex]n_{th,rev} = 1 - \frac{(30+273)K}{(652+273)K}[/tex]
= 0.672
The efficiency of this carnot engine = 0.672 = 67.2%
b) The amount of heat rejected [tex]Q_{L}[/tex] by heat reversible engine can be calculated from:
[tex](\frac{Q_{H} }{Q_{L} } )_{rev} = \frac{T_{H} }{T_{L} }[/tex]
[tex]Q_{L,rev} = \frac{T_{L} }{T_{H} } Q_{H,rev}[/tex]
= [tex]\frac{(30+273)K}{(652+273)K} (500KJ)[/tex]
= 164KJ
Carnot heat engine converts 67.2% of the heat it receives to work.
The amount of heat rejected to the sink per cycle = 164 kJ
Learn more about efficiency from:
https://brainly.com/question/16910106
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