Explore Westonci.ca, the top Q&A platform where your questions are answered by professionals and enthusiasts alike. Join our Q&A platform and get accurate answers to all your questions from professionals across multiple disciplines. Experience the convenience of finding accurate answers to your questions from knowledgeable experts on our platform.

How many 20 N bricks should you add to increase the friction force on a cart
by 80 N if the coefficient of friction is 0.8?


Sagot :

Answer:

5 bricks.

Explanation:

Comment

This is the kind of question where you have to invent your own formula. It is not obvious what to do.

Formula

Ff (frictional force) = mu (coeficient of friction) * weight of 1 brick * Number needed.

FF(friction force) = mu * weight 1 brick * number of bricks.

Givens

ff = 80 N

mu = 0.8

Brick weight (1 brick) = 20N

n is the number of bricks needed.

Solution

Ff = mu * weight 1 brick * number of bricks   Substitute the givens

80 = 0.8 * 20N * n                                            n is the number of bricks

80 = 16 * n                                                        Divide by 16

80/16 = 16*n/16

5 = n

You have to add 5 bricks.