The position of a 2.75 × 105N training helicopter under test is given by 7 = (0.020) t³i + (2.2 m/s)tĵ - (0.060t²k. Find the net force on the helicopter at t= 5.0 s. (Take g = 9.8 m/s²)

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02-11-2022
Physics

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The position of a 2.75 × 105N training helicopter under test is given by 7 = (0.020) t³i + (2.2 m/s)tĵ - (0.060t²k. Find the net force on the helicopter at t= 5.0 s. (Take g = 9.8 m/s²)

The Position Of A 275 105N Training Helicopter Under Test Is Given By 7 0020 Ti 22 Mstĵ 0060tk Find The Net Force On The Helicopter At T 50 S Take G 98 Ms class=

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The position of a 2.75 × 105N training helicopter under test is given by 7 = (0.020) t³i + (2.2 m/s)tĵ - (0.060t²k. Find the net force on the helicopter at t= 5.0 s. (Take g = 9.8 m/s²)​

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The position of a 2.75 × 105N training helicopter under test is given by 7 = (0.020) t³i + (2.2 m/s)tĵ - (0.060t²k. Find the net force on the helicopter at t= 5.0 s. (Take g = 9.8 m/s²)