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b. Based on the data, estimate the probability that a randomly selected student from this class has three or more siblings. Number of Siblings 0 1 2 3 5 6 Count 8 13 12 3 1

B Based On The Data Estimate The Probability That A Randomly Selected Student From This Class Has Three Or More Siblings Number Of Siblings 0 1 2 3 5 6 Count 8 class=

Sagot :

In class total nmber of students is n(T) = 38.

The number of students with three or more than three siblings are

[tex]\begin{gathered} n(\ge3)=3+1+0+1 \\ =5 \end{gathered}[/tex]

Determine the probability for the students with three or more than three siblings.

[tex]\begin{gathered} P(\ge3)=\frac{n(\ge3)}{n(T)} \\ =\frac{5}{38} \\ =0.13157 \\ \approx0.132 \end{gathered}[/tex]

Thus answer is 5/38 or 0.132.