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A guy wire runs from the top of a cell tower to a metal stake in the ground. Evelynplaces a 10-foot tall pole to support the guy wire. After placing the pole, Evelynmeasures the distance from the stake to the pole to be 2 ft. She then measures thedistance from the pole to the tower to be 19 ft. Find the length of the guy wire, to thenearest foot.

A Guy Wire Runs From The Top Of A Cell Tower To A Metal Stake In The Ground Evelynplaces A 10foot Tall Pole To Support The Guy Wire After Placing The Pole Evely class=

Sagot :

SOLUTION:

[tex]\begin{gathered} \frac{2}{10}\text{ = }\frac{21}{b} \\ \\ b\text{ = }\frac{21\text{ X 10}}{2}\text{ = 105 f}eet \\ To\text{ find the length of the guy wire;} \\ \text{Hypotenuse}^2=Opposite^2+Adjacent^2 \\ l^2=105^2+(19+2)^2 \\ l^2\text{ = 11025 + 441} \\ l^2\text{ = 11466} \\ l\text{ = }\sqrt[]{11466} \\ l\text{ = 107.079} \\ l\text{ = 107 ( nearest foot)} \end{gathered}[/tex]

The length of the guy wire to the nearest foot is 107 feet.

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