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Sagot :
Given:-
[tex](-7,3)(7,1)[/tex]To find:-
The equation of the line passing through the point.
So first we find the value of the slope m. we use the formula,
[tex]m=\frac{y_2-y_1}{x_2-x_1}[/tex]Now we substitute the given values, so we get,
[tex]m=\frac{1-3}{7-(-7)}[/tex]Simplifying we get,
[tex]\begin{gathered} m=\frac{1-3}{7-(-7)} \\ m=\frac{-2}{14} \\ m=-\frac{1}{7} \end{gathered}[/tex]So the value of slope m is -1/7.
Now we find the equation. we use the formula,
[tex]y=mx+c[/tex]Substtuing any one point we get,
[tex]\begin{gathered} 3=-\frac{1}{7}\times-7+c \\ 3=1+c \\ 3-1=c \\ c=2 \end{gathered}[/tex]So the required equation is,
[tex]y=-7x+2[/tex]
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