Answered

Westonci.ca offers quick and accurate answers to your questions. Join our community and get the insights you need today. Discover solutions to your questions from experienced professionals across multiple fields on our comprehensive Q&A platform. Connect with a community of professionals ready to provide precise solutions to your questions quickly and accurately.

James brought a 55" TV. If its aspect ratio is 4:3 what is its areaChoices:A. 3025in squaredB. 1452in squaredC. 33in squareD. 121in squared

Sagot :

We have the following:

55 inches indicates the diagonal of the TV, therefore:

let x a side A

let y a side B

[tex]\begin{gathered} 3x=4y \\ x=\frac{4}{3}y \end{gathered}[/tex]

now, with the Pythagorean theorem

[tex]\begin{gathered} 55^2=x^2+y^2 \\ 3025=(\frac{4}{3}y)^2+y^2 \\ 3025=\frac{16}{9}y^2+y^2 \\ \frac{25}{9}y^2=3025 \\ y=\sqrt[]{3025\cdot\frac{9}{25}} \\ y=\sqrt[]{1089} \\ y=33 \end{gathered}[/tex]

for x:

[tex]\begin{gathered} x=\frac{4}{3}\cdot33 \\ x=44 \end{gathered}[/tex]

Side A= 44 in

Side B = 33 in

The area:

[tex]a=A\cdot B=44\cdot33=1452[/tex]

The answer is 1452 inches squared, the option B

View image KhalielS7991
We hope our answers were helpful. Return anytime for more information and answers to any other questions you may have. Thank you for your visit. We're committed to providing you with the best information available. Return anytime for more. Get the answers you need at Westonci.ca. Stay informed with our latest expert advice.