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A manufacturer makes bags of popcorn and bags of potato chips. The average weight of a bag of popcorn is supposed to be 3.05 ounces with an allowable deviation of0.02 ounces. The average weight of a bag of potato chips is supposed to be 5.05 ounces with an allowable deviation of 0.03 ounces. A factory worker randomly selectsa bag of popcorn from the assembly line and it has a weight of 3.02 ounces. Then the worker randomly selects a bag of potato chips from the assembly line and it has aweight of 5.02 ounces. Which description closely matches the findings on the assembly line?AnswerTablesKeypadKeyboard ShortcutsO The popcorn bag assembly line is closer to the specifications given because its z-score is closer to the standard than the potato chip bag assembly line.O The popcorn bag assembly line is closer to the specifications given because its z-score is further from the standard than the potato chip bag assembly line.O The potato chip bag assembly line is closer to the specifications given because its z-score is closer to the standard than the popcorn bag assembly line.O The potato chip bag assembly line is closer to the specifications given because its z-score is further from the standard than the popcorn bag assembly line.

A Manufacturer Makes Bags Of Popcorn And Bags Of Potato Chips The Average Weight Of A Bag Of Popcorn Is Supposed To Be 305 Ounces With An Allowable Deviation Of class=

Sagot :

Step 1

Given:

The average weight of a bag of popcorn - 3.05 oz

allowable deviation - 0.02 oz

Ave. weight of a bag of potato chips - 5.05 oz

allowable deviation - 0.03 oz

Actual weight of the bag of popcorn - 3.02 oz

Actual weight of the bag of potato chips - 5.02 oz

Step 2

Find the z-score of popcorn

[tex]z=\frac{3.02-3.05}{0.02}=-1.5[/tex]

Find the z-score of potato chips

[tex]z=\frac{5.02-5.05}{0.03}=-1[/tex]

Thus the answer will be;

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