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a stone is dropped from a high cliff. If it accelerates at a rate of 9.8 m/s^2. what is its velocity after 5 seconds? write the equation

Sagot :

jcherry99

Answer:

The velocity after 5 seconds is 49.05

Explanation:

Comment

This is an application question for a = (vf - vi)/t

a is the acceleration 9.81 m/s^2

vi is the starting speed ( of zero because the stone is dropped, not thrown).

vf is the final velocity after 8 seconds

t is the time

Solution

9.81 m/s^2 = (vf - vi)/t             Substitute the givens

9.81 m/s^2 = (vf - 0)/5            Multiply both sides by 5

9.81 * 5 = 5* vf/5

vf = 49.05

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