Solution
Step 1
The surface area of the square pyramid
= Sum of the area of the four triangular faces and the area of the square base.
Step 2
[tex]\begin{gathered} \text{Area of the triangular face = }\frac{Base\text{ }\times\text{ Height}}{2} \\ Base\text{ = 0.8 foot} \\ Height\text{ = 6 feet} \\ Area\text{ of the triangular face = }\frac{0.8\text{ }\times\text{ 6}}{2}\text{ = 2.4 ft}^2 \\ Area\text{ of the four triangular faces = 4 }\times\text{ 2.4 = 9.6 ft}^2 \\ Area\text{ of the square base = L}^2\text{ = 0.8}^2\text{ = 0.64} \end{gathered}[/tex]Step 3
[tex]Surface\text{ area of the square pyramid = 9.6 + 0.64 = 10.24 ft}^2[/tex]Final answer
10.24 square feet