[tex]\frac{35}{2}\pi\approx54.97\approx55ft[/tex]
1) Note that this fountain is made up of 2 semicircles, and 1 quarter circle. Note also that the diameter of those semicircles is 14 ft then the radius is 7
The perimeter can be found this way:
[tex]\begin{gathered} 2\:semicircles=\frac{2\pi r}{2}+\frac{2\pi r}{2}=2\pi r\Rightarrow C=2\pi(7)\Rightarrow C=14\pi \\ 1\:quarter\:=\frac{2\pi r}{4}=\frac{\pi r}{2}\Rightarrow\frac{7\pi}{2} \\ \\ \end{gathered}[/tex]
2) Now, let's add them up:
[tex]14\pi+\frac{7\pi}{2}=\frac{35}{2}\pi[/tex]
Thus this is approximately 55 ft
