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A 7.30 kg sign hangs from two wires. Thefirst wire is attached to the left end, andpulls 28.0 N directly left. What is theX-component of the force of the secondwire?F2F1wEnterX-component (N)I

A 730 Kg Sign Hangs From Two Wires Thefirst Wire Is Attached To The Left End Andpulls 280 N Directly Left What Is TheXcomponent Of The Force Of The SecondwireF2 class=

Sagot :

As, the mass is in rest, the x-component of the force must be zero.

[tex]\begin{gathered} F_2(x)-F_1=0 \\ F_2(x)=F_1 \\ F_2(x)=28.0\text{ N} \end{gathered}[/tex]

Therefore, x component of the second force is 28.0 N.

Balancing y component of the force,

[tex]\begin{gathered} F_y=W \\ =mg \\ =7.3\times9.8 \\ =71.54\text{ N} \end{gathered}[/tex]

Therefore, y component of the force is 71.54 N.

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