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Sagot :
2)
we will use the trigonometric ratio of tangent
[tex]\tan (\alpha)=\frac{O}{A}[/tex]where alpha is the angle , O the opposite side from the triangle and A the adjacent side
now replacing
[tex]\tan (x)=\frac{5}{9}[/tex]and solve for x
[tex]\begin{gathered} x=\tan ^{-1}(\frac{5}{9}) \\ x\approx29 \end{gathered}[/tex]the measure of the angle x is 29°
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