Looking for reliable answers? Westonci.ca is the ultimate Q&A platform where experts share their knowledge on various topics. Join our platform to connect with experts ready to provide precise answers to your questions in different areas. Join our platform to connect with experts ready to provide precise answers to your questions in different areas.
Sagot :
The area of a rectangle is given by the following expression:
[tex]\text{area}=\text{length}\cdot\text{width}[/tex]We know that the length of the parking lot is 9 yards greater than the width, this means that if we add 9 yards to the width we will have the length.
[tex]\text{length}=\text{width}+9[/tex]By applying the second expression on the first one and making it equal to the area of the parking lot we can determine the width.
[tex]\begin{gathered} 360=(\text{width}+9)\cdot\text{width} \\ 360=width^2+9\cdot width \\ \text{width }^2+9\text{width}-360=0 \end{gathered}[/tex]We need to solve the second degree equation to determine the width.
[tex]\begin{gathered} \text{width}=\frac{-9\pm\sqrt[]{9^2-4\cdot1\cdot(-360)}}{2\cdot1} \\ \text{width}=\frac{-9\pm\sqrt[]{81+1440}}{2}=\frac{-9\pm39}{2} \\ \text{width}=\frac{-9+39}{2}=\frac{30}{2}=15 \end{gathered}[/tex]The width of the parking lot is 15 yards.
The length is the width added by 9 yards, which is equal to 24 yards.
Thank you for your visit. We're committed to providing you with the best information available. Return anytime for more. Thank you for your visit. We're committed to providing you with the best information available. Return anytime for more. Westonci.ca is committed to providing accurate answers. Come back soon for more trustworthy information.
