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CuSO4 (aq) + Zn(s) →→→ Cu(s) + ZnSO4 (aq)The single-replacement reaction above produces 145.0 g ofan unknown concentration of zinc sulfate. With excess Cusmass of Zn was used?Molar mass of Cu: 63.55 g/molMolar mass of Zn: 65.38 g/molAnswer:g of zinc (Use 4 sig figs)

CuSO4 Aq Zns Cus ZnSO4 AqThe Singlereplacement Reaction Above Produces 1450 G Ofan Unknown Concentration Of Zinc Sulfate With Excess Cusmass Of Zn Was UsedMolar class=

Sagot :

In this question, we have the following reaction:

CuSO4 + Zn -> Cu + ZnSO4, as the question already says, this is a single replacement reaction

We have:

145.0 grams of Cu (Copper)

We have to find out how much Zn we had at the beginning of the reaction

First thing we need to do is find out how many moles of Copper we have, we will do it by using its molar mass, 63.55g/mol, and the given mass in the question, 145g

63.55g = 1 mol

145g = x moles

x = 2.28 moles of Copper in 145 grams

Now, according to the molar ratio, if we have 1 mol of Zn, we will produce 1 mol of Cu, therefore if we have 2.28 moles of Cu, we will have 2.28 moles of Zinc as well

Now we will find the mass of Zinc, using the number of moles, 2.28 moles and its molar mass, 65.38g/mol

65.38g = 1 mol

x grams = 2.28 moles

x = 149.1 grams of Zinc was used

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