You have to complete the table for the solutions of the linear equation
[tex]4x+y=-40[/tex]
To do so, replace the equation with each given value of x or y and solve for the missing coordinate:
For x=0
[tex]\begin{gathered} 4x+y=-40 \\ 4\cdot0+y=-40 \\ y=-40 \end{gathered}[/tex]
When x=0, y=-40, the coordinates are (0,-40)
For x=2
[tex]\begin{gathered} 4x+y=-40 \\ 4\cdot2+y=-40 \\ 8+y=-40 \\ y=-40-8 \\ y=-48 \end{gathered}[/tex]
When x=2, y=-48, the coordinates are (2,-48)
For y=0
[tex]\begin{gathered} 4x+y=-40 \\ 4x+0=-40 \\ 4x=-40 \\ \frac{4x}{4}=-\frac{40}{4} \\ x=-10 \end{gathered}[/tex]
When y=0, x=-10, the coordinates are (-10,0)
