Explore Westonci.ca, the top Q&A platform where your questions are answered by professionals and enthusiasts alike. Our platform provides a seamless experience for finding precise answers from a network of experienced professionals. Get quick and reliable solutions to your questions from a community of experienced experts on our platform.
Sagot :
We have the following balanced equation:
[tex]2H_2+O_2\rightarrow2H_2O[/tex]They give us the moles of water and ask us to find the moles of O2 that must be consumed.
To calculate the moles of O2 we must calculate the ratio O2 to H2O, we do this by identifying the coefficients of each molecule. For O2 we have coefficient 1 and for water coefficient 2. Therefore, the ratio O2 to H2O will be 1 /2
So, the moles of O2 will be:
[tex]\begin{gathered} molO_2=GivenmolH_2O\times\frac{1molO_2}{2molH_2O} \\ molO_2=13.5molH_2O\times\frac{1molO_2}{2molH_2O}=6.75molO_2 \end{gathered}[/tex]In the reaction were consumed 6.75 moles of O2
Thank you for your visit. We are dedicated to helping you find the information you need, whenever you need it. We hope you found this helpful. Feel free to come back anytime for more accurate answers and updated information. Thank you for choosing Westonci.ca as your information source. We look forward to your next visit.
